flash/stm32l4x: free write_algorithm work area if no space left for the buffer

If the remaining memory for the buffer is less than 256 bytes,
the memory allocated for the write algorithm in the target is not freed.

Fixes: ba131f30a079 (Flash driver for STM32G0xx and STM32G4xx)
Change-Id: Ic649f6c39799d76725b0c69ff3a009a3f510e17f
Signed-off-by: Tarek BOCHKATI <tarek.bouchkati@gmail.com>
Reviewed-on: https://review.openocd.org/c/openocd/+/6486
Tested-by: jenkins
Reviewed-by: Oleksij Rempel <linux@rempel-privat.de>

diff --git a/src/flash/nor/stm32l4x.c b/src/flash/nor/stm32l4x.c
index b8635fe75ccd60de828e35757f5b5d82acc10e87..3c055616f5c1cd1a92475b7295a07a8b4a1e3683 100644 (file)
--- a/src/flash/nor/stm32l4x.c
+++ b/src/flash/nor/stm32l4x.c
@@ -1353,6 +1353,7 @@ static int stm32l4_write_block(struct flash_bank *bank, const uint8_t *buffer,
        buffer_size = target_get_working_area_avail(target) & ~(2 * sizeof(uint32_t) - 1);
        if (buffer_size < 256) {
                LOG_WARNING("large enough working area not available, can't do block memory writes");
+               target_free_working_area(target, write_algorithm);
                return ERROR_TARGET_RESOURCE_NOT_AVAILABLE;
        } else if (buffer_size > 16384) {
                /* probably won't benefit from more than 16k ... */